8x^2=60-20x

Solution for 8x^2=60-20x equation:

8x^2=60-20x

We move all terms to the left:

8x^2-(60-20x)=0

We add all the numbers together, and all the variables

8x^2-(-20x+60)=0

We get rid of parentheses

8x^2+20x-60=0

a = 8; b = 20; c = -60;
Δ = b2-4ac
Δ = 202-4·8·(-60)
Δ = 2320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2320}=\sqrt{16*145}=\sqrt{16}*\sqrt{145}=4\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{145}}{2*8}=\frac{-20-4\sqrt{145}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{145}}{2*8}=\frac{-20+4\sqrt{145}}{16}
$